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36 lines
1.5 KiB
C
36 lines
1.5 KiB
C
/* execv() function: Execute a program, replacing the current process.
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Copyright (C) 2020-2026 Free Software Foundation, Inc.
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This file is free software: you can redistribute it and/or modify
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it under the terms of the GNU Lesser General Public License as
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published by the Free Software Foundation; either version 2.1 of the
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License, or (at your option) any later version.
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This file is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU Lesser General Public License for more details.
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You should have received a copy of the GNU Lesser General Public License
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along with this program. If not, see <https://www.gnu.org/licenses/>. */
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/* Written by Bruno Haible <bruno@clisp.org>, 2020. */
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#include <config.h>
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/* Specification. */
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#include <unistd.h>
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int
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execv (const char *program, char * const *argv)
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{
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/* Pass the environment explicitly. This is needed if the program has
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modified the environment using putenv() or [un]setenv(). On Windows,
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processes have two environments, one in the "environment block" of the
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process and managed through SetEnvironmentVariable(), and one inside the
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process, in the location retrieved by the 'environ' macro. If we were
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to pass NULL, the child process would inherit a copy of the environment
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block - ignoring the effects of putenv() and [un]setenv(). */
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return execve (program, argv, environ);
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}
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